1.

10) Analysis of vitamin C shows that it contains40.92% carbon by mass, 4.58% hydrogen and54.50% oxygen. Determine the empirical formulaof vitamin C. (Ans. C3H403)

Answer»

40.92 x 1 mole C/ 12g C = 3.14 mole C

4.48 x 1mole H/ 1.008 g H = 4.43 mole H

54.50 x 1 mole O/ 16g O = 3.41 mole O

Dividing each of the three numbers by the smallest one (3.41 mol) gives a C:H:O mole ratio of 1 :1.33 :1 this gives the empirical formula: C3 x 1 H3 x 1.33 O3 x 1 or C3H4O3

any other method?



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