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10. Evaluatethefollowing2 sin 135 cos 2109 tan 240° cot 300° sec 330(ii) sin 690° cos 930° + tan (-765°) cosec (-1170°) |
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Answer» √2 sin135 cos210 tan240 cot300 sec330 sin135 = sin(180-45) = sin45 = 1/√2 cos210 = cos(180+30) = -cos30 = -√3/2 tan240 = tan(180+60) = tan60 = √3 cot300 = cot(360-60) = -cot60 = -1/√3 sec330 = sec(360-30) = sec30 = 2/√3 √2 × 1/√2 × (-√3/2) × √3 × (-1/√3) × 2/√3 = 1 (ii) |
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