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`10 g` of a sample of a mixture of `CaCl_(2)` and `NaCl` is treated to precipitate all the calcium as `CaCO_(3)`. This `CaCO_(3)` is heated to convert all the `Ca` to `CaO` and the final mass of `CaO` is 1.62 g.The percent by mass of `CaCl_(2)` in the origial mixture isA. 0.321B. 0.162C. 0.218D. 0.11 |
Answer» Correct Answer - A `CaCl_(2) + NaCl = 10 g` Let Weight of `CaCl_(2) = x g` `underset({:(1 "mol"),((x)/(111)"mol"):})(CaCl_(2)) rarr underset({:(1 "mol"),((x)/(111)"mol"):})(CaCO_(3)) rarr underset(1 "mol")(CaO)` Mole of `CaO = (1.62)/(56)` `:. (x)/(111) = (1.62)/(56)` `x = 3.21 g` % of `CaCl_(2) = (3.21)/(10) xx 100 = 32.1%` |
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