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10 g of argonis compressd isothermally and reversibly at a temperature of27^(@)C from10L to 5L . Calculate q,w,DeltaE and DeltaHfor this process. R =2.0 cal K^(-1)mol^(-1) , log= 2 = 0.30. Atomic wt. of Ar=40 |
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Answer» Solution :`q= 2.303 nRT log. (V_(2))/(V_(1)) = 2.303 xx (10)/( 40) xx 300 xx log. (5)/(10)= -103.635 cal` For ISOTHERMAL expansion,`DeltaE= 0``w= DeltaE-q= 0-( - 103.635)= +103.635 cal` Also, when temperature is constant, `P_(1)V_(1) = P_(2)V_(2)` or `PV =` constant `DeltaH = DeltaE+Delta(PV) = 0+0=0` |
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