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10 g of argonis compressd isothermally and reversibly at a temperature of27^(@)C from10L to 5L . Calculate q,w,DeltaE and DeltaHfor this process. R =2.0 cal K^(-1)mol^(-1) , log= 2 = 0.30. Atomic wt. of Ar=40

Answer» <html><body><p></p>Solution :`q= 2.303 nRT log. (V_(2))/(V_(1)) = 2.303 xx (<a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a>)/( 40) xx 300 xx log. (5)/(10)= -103.635 cal`<br/> For <a href="https://interviewquestions.tuteehub.com/tag/isothermal-520014" style="font-weight:bold;" target="_blank" title="Click to know more about ISOTHERMAL">ISOTHERMAL</a> expansion,`DeltaE= <a href="https://interviewquestions.tuteehub.com/tag/0-251616" style="font-weight:bold;" target="_blank" title="Click to know more about 0">0</a>``w= DeltaE-q= 0-( - 103.635)= +103.635 cal` <br/>Also, when temperature is constant, `P_(1)V_(1) = P_(2)V_(2)` or `PV =` constant `DeltaH = DeltaE+Delta(PV) = 0+0=0`</body></html>


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