10 g of hydrogen and 64 g of oxygen were filled in a steel vessel and exploded. Amount of water produced in the reaction will be :

10 g of hydrogen and 64 g of oxygen were filled in a steel vessel and

1.	10 g of hydrogen and 64 g of oxygen were filled in a steel vessel and exploded. Amount of water produced in the reaction will be :
Answer» 3 mol 4 mol 1 mol 2 mol Solution :`underset("1 mol")(H_(2)(g))+underset("0.5 mol")(1//2O_(2)(g))rarrunderset("1 mol")(H_(2)O(l))` 10 gof `H_(2)=((10G))/(("2 g mol"^(-1)))=5` mol 64 g of `O_(2)=((64g))/(("32 g mol"^(-1)))=2` mol In this reaction, `O_(2)` is LIMITING reactant 0.5 mol of OXYGEN from water = 1 mol 2 mol of oxygen from water `= (("1 mol"))/(("0.5 mol"))xx("2 mol")=4` mol.