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10 g of hydrogen and 64 g of oxygen were filled in a steel vessel and exploded. Amount of water produced in the reaction will be :

Answer» <html><body><p>3 mol<br/>4 mol<br/>1 mol<br/>2 mol</p>Solution :`underset("1 mol")(H_(2)(g))+underset("0.5 mol")(1//2O_(2)(g))rarrunderset("1 mol")(H_(2)O(l))` <br/> 10 gof `H_(2)=((<a href="https://interviewquestions.tuteehub.com/tag/10g-267074" style="font-weight:bold;" target="_blank" title="Click to know more about 10G">10G</a>))/(("2 g mol"^(-1)))=5` mol <br/> 64 g of `O_(2)=((64g))/(("<a href="https://interviewquestions.tuteehub.com/tag/32-307188" style="font-weight:bold;" target="_blank" title="Click to know more about 32">32</a> g mol"^(-1)))=2` mol <br/> In this reaction, `O_(2)` is <a href="https://interviewquestions.tuteehub.com/tag/limiting-2791961" style="font-weight:bold;" target="_blank" title="Click to know more about LIMITING">LIMITING</a> reactant 0.5 mol of <a href="https://interviewquestions.tuteehub.com/tag/oxygen-1144542" style="font-weight:bold;" target="_blank" title="Click to know more about OXYGEN">OXYGEN</a> from water = 1 mol <br/> 2 mol of oxygen from water <br/> `= (("1 mol"))/(("0.5 mol"))xx("2 mol")=4` mol.</body></html>


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