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10 g of hydrogen and 64 g of oxygen were filled in a steel vessel and exploded. The amount of water produced in this reaction will be

Answer» <html><body><p>3 mole<br/><a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a> mole<br/>2 mole<br/>1 mole</p>Solution :10 g of `H_(2)+ 64g` of `O_(2) to` <a href="https://interviewquestions.tuteehub.com/tag/water-1449333" style="font-weight:bold;" target="_blank" title="Click to know more about WATER">WATER</a> <br/>`2H_(2) + O_(2) to 2H_(2)O` <br/>4 g of hydrogen react with 32 g of oxygen. So 10 g of hydrogen will react with <a href="https://interviewquestions.tuteehub.com/tag/80g-338891" style="font-weight:bold;" target="_blank" title="Click to know more about 80G">80G</a> of oxygen. But we have <a href="https://interviewquestions.tuteehub.com/tag/given-473447" style="font-weight:bold;" target="_blank" title="Click to know more about GIVEN">GIVEN</a> amount of oxygen only 64 g. It means, here oxygen is the limiting agent. Now all the oxygen react with 8 g of hydrogen and form 4 moles of water.</body></html>


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