1.

10 g of hydrogen and 64 g of oxygen were filled in a steel vessel and exploded. The amount of water produced in this reaction will be

Answer»

3 mole
4 mole
2 mole
1 mole

Solution :10 g of `H_(2)+ 64g` of `O_(2) to` WATER
`2H_(2) + O_(2) to 2H_(2)O`
4 g of hydrogen react with 32 g of oxygen. So 10 g of hydrogen will react with 80G of oxygen. But we have GIVEN amount of oxygen only 64 g. It means, here oxygen is the limiting agent. Now all the oxygen react with 8 g of hydrogen and form 4 moles of water.


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