1.

10 g of sample of mixture of CaCl_(2) and NaCl are treated to precipitate all the calcium as CaCO_(3). This CaCO_(3) is heated to convert all the Ca to CaO and the final mass of CaCl_(2) in the original mixture is

Answer»

0.321
0.162
0.218
0.12

Solution :a) `CaCl_(2) + NaCl = 10g`
Let, weight of `CaCl_(2)` = XG
`CaCl_(2) to CaCO_(3) to CaO`
Moleof CaO = `(1.62)/(56) rArr x/111 = 1.62/56 x = 3.21g`
`%` of `CaCl_(2)` = (3.21/10 x 100) = 32.1%`


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