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10 g of sample of mixture of `CaCl_(2)` and NaCl are treated to precipitate all the calcium as `CaCO_(3)`. This `CaCO_(3)` is heated to convert all the Ca to CaO and the final mass of `CaCl_(2)` in the original mixture isA. 0.321B. 0.162C. 0.218D. 0.12 |
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Answer» a) `CaCl_(2) + NaCl = 10g` Let, weight of `CaCl_(2)` = xg `CaCl_(2) to CaCO_(3) to CaO` Moleof CaO = `(1.62)/(56) rArr x/111 = 1.62/56 x = 3.21g` `%` of `CaCl_(2)` = (3.21/10 x 100) = 32.1%` |
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