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10 grams of a hydrated sodium carbonate, Na_(2)CO_(3).xH_(2)O, on strong heating loses a weight of 6.29 grams. Report the value of x. |
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Answer» SOLUTION :HYDRATED sodium carbonate LOSES water of HYDRATION on strong heating. `Na_(2)CO_(3).xH_(2)Orarr Na_(2)CO_(3)+xH_(2)O` 1 MOLE of `Na_(2)CO_(3)-=X` moles of `H_(2)O` 106 grams of `Na_(2)CO_(3)-=X xx18` grams of water 3.71 grams of `Na_(2)CO_(3)-=6.29` grams of water 3.71 grams of `Na_(2)CO_(3)` is related to 106 grams 6.29 grams of water is related to ? Weight of water in one formula unit `=(6.29)/(3.71)xx106` = 180 grams 18 grams of water = 1 mole 180 grams of water = ? Value of `X=(180)/(18)=10` |
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