1.

10 grams of a hydrated sodium carbonate, Na_(2)CO_(3).xH_(2)O, on strong heating loses a weight of 6.29 grams. Report the value of x.

Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<a href="https://interviewquestions.tuteehub.com/tag/hydrated-2721634" style="font-weight:bold;" target="_blank" title="Click to know more about HYDRATED">HYDRATED</a> sodium carbonate <a href="https://interviewquestions.tuteehub.com/tag/loses-1079374" style="font-weight:bold;" target="_blank" title="Click to know more about LOSES">LOSES</a> water of <a href="https://interviewquestions.tuteehub.com/tag/hydration-1033911" style="font-weight:bold;" target="_blank" title="Click to know more about HYDRATION">HYDRATION</a> on strong heating. <br/> `Na_(2)CO_(3).xH_(2)Orarr Na_(2)CO_(3)+xH_(2)O` <br/> 1 <a href="https://interviewquestions.tuteehub.com/tag/mole-1100299" style="font-weight:bold;" target="_blank" title="Click to know more about MOLE">MOLE</a> of `Na_(2)CO_(3)-=X` moles of `H_(2)O` <br/> 106 grams of `Na_(2)CO_(3)-=X xx18` grams of water <br/> 3.71 grams of `Na_(2)CO_(3)-=6.29` grams of water <br/> 3.71 grams of `Na_(2)CO_(3)` is related to 106 grams <br/> 6.29 grams of water is related to ? <br/> Weight of water in one formula unit `=(6.29)/(3.71)xx106`<br/> = 180 grams <br/> 18 grams of water = 1 mole <br/> 180 grams of water = ? <br/> Value of `X=(180)/(18)=10`</body></html>


Discussion

No Comment Found

Related InterviewSolutions