10 grams of a sample of potassium chlorate gave on complete decomposition 2.24 litre of oxygen at N.T.P. What is the percentage purity of the sample ?

10 grams of a sample of potassium chlorate gave on complete decomposit

1.	10 grams of a sample of potassium chlorate gave on complete decomposition 2.24 litre of oxygen at N.T.P. What is the percentage purity of the sample ?
Answer» <html><body><p><br/></p>Solution :Chemical <a href="https://interviewquestions.tuteehub.com/tag/equation-974081" style="font-weight:bold;" target="_blank" title="Click to know more about EQUATION">EQUATION</a> for the reaction is : <br/> `underset(underset(=245g)(2xx(39+35.5+48)))(2KClO_(3)(s))overset("Heat")(<a href="https://interviewquestions.tuteehub.com/tag/rarr-1175461" style="font-weight:bold;" target="_blank" title="Click to know more about RARR">RARR</a>)2KCl(s)+underset(underset(=67.2L)(3xx22.4))(3O_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)(<a href="https://interviewquestions.tuteehub.com/tag/g-1003017" style="font-weight:bold;" target="_blank" title="Click to know more about G">G</a>))` <br/> 67.2 L of `O_(2)` is evolved at N.T.P from `KClO_(3) 245 g` <br/> 2.24 L of `O_(2)` is evolved at N.T.P from `KClO_(3)=(245)/(67.5)xx2.24=8.167g` <br/> Percentage purity of sample `= ("Mass of pure "KClO_(3))/("Mass of the sample")xx100=(8.167)/(10.0)xx100=81.7%`.</body></html>