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`10` grams of stream at `100^@ C` is mixed with `50 gm` of ice at `0^@ C` then final temperature isA. `20^@ C`B. `50^@ C`C. `40^@ C`D. `100^@ C` |
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Answer» Correct Answer - C Heat lost = Heat gained `m_(ice) L_(ice) + m_(ice)S_(w)(theta)= m_(steam) L_(steam) + m_(steam) S_(w) (100-theta)`. |
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