A ball is droped as a floor from a height of `2.0m` After the collsion it rises up to a height of `1.5m` Assume thet `40%` of the machanical energy lost goes as thermal energy into the ball.Calculate the rise in the temperature of the ball in the colliation headcapacity of the ball is `800J K^(-1)`

A ball is droped as a floor from a height of `2.0m` After the collsion

1.	A ball is droped as a floor from a height of `2.0m` After the collsion it rises up to a height of `1.5m` Assume thet `40%` of the machanical energy lost goes as thermal energy into the ball.Calculate the rise in the temperature of the ball in the colliation headcapacity of the ball is `800J K^(-1)`
Answer» Correct Answer - A::B::C Let the mass of hall be m kg and `V_(1) = sqrt(2gh) = sqrt(40)` `V_(2)= sqrt(2gh) = sqrt(30)` So change in K.E. `= (1)/(2)xx mxx 40- ((1)/(2)m)xx 30 = ((10)/(2))m` `= 5m` That is utilisedto increases in temperature of the ball `((40)/(100)) xx (10)/(2)m = m xx 800 xx Delta t` `rArr Delta t = (1)/(400) = 0.0025` `= 2.5 xx 10^(-3)^(@)C`

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A ball is droped as a floor from a height of `2.0m` After the collsion it rises up to a height of `1.5m` Assume thet `40%` of the machanical energy lost goes as thermal energy into the ball.Calculate the rise in the temperature of the ball in the colliation headcapacity of the ball is `800J K^(-1)`

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