10 kg of cold water at 2^(@)C absorbs 50J of heatfrom the surrounding which were at a temperature of37^(@)C . What is the entropy change of (i) the system (ii) the surroundings (iii) the universe ? Assumethe change in temperature of the water and the surroundings to be negligible.

10 kg of cold water at 2^(@)C absorbs 50J of heatfrom the surrounding

1.	10 kg of cold water at 2^(@)C absorbs 50J of heatfrom the surrounding which were at a temperature of37^(@)C . What is the entropy change of (i) the system (ii) the surroundings (iii) the universe ? Assumethe change in temperature of the water and the surroundings to be negligible.
Answer» <html><body><p><br/></p>Solution :`(i) DeltaS_("system") ("water")= ( +50J)/( 275K) = 0.18 <a href="https://interviewquestions.tuteehub.com/tag/jk-521675" style="font-weight:bold;" target="_blank" title="Click to know more about JK">JK</a>^(-1)``(ii) DeltaS_("<a href="https://interviewquestions.tuteehub.com/tag/surroundings-1235986" style="font-weight:bold;" target="_blank" title="Click to know more about SURROUNDINGS">SURROUNDINGS</a>") =( -50J)/(310K) = - 0.16 JK^(-1)` <br/> `(<a href="https://interviewquestions.tuteehub.com/tag/iii-497983" style="font-weight:bold;" target="_blank" title="Click to know more about III">III</a>) DeltaS_("universe") = <a href="https://interviewquestions.tuteehub.com/tag/deltas-947743" style="font-weight:bold;" target="_blank" title="Click to know more about DELTAS">DELTAS</a> _("system") + DeltaS_("surroundings") = 0.18 + ( -.16) = 0.02 JK^(-1)`</body></html>