10 mL of a given solution of H_(2)O_(2) contains 0.91 g of H_(2)O_(2) . Express its strength in volume.

10 mL of a given solution of H_(2)O_(2) contains 0.91 g of H_(2)O_(2)

1.	10 mL of a given solution of H_(2)O_(2) contains 0.91 g of H_(2)O_(2) . Express its strength in volume.
Answer» <html><body><p></p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/68-331600" style="font-weight:bold;" target="_blank" title="Click to know more about 68">68</a> g of `H_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)O_(2)` produce `O_(2)=22400` <a href="https://interviewquestions.tuteehub.com/tag/ml-548251" style="font-weight:bold;" target="_blank" title="Click to know more about ML">ML</a> at NTP <br/>`therefore 0.91 g ` of `H_(2)O_(2)` will produce `O_(2)=(22400xx0.91)/(68)~= 300` mL at NTP <br/> `therefore ` Volume <a href="https://interviewquestions.tuteehub.com/tag/strength-1229153" style="font-weight:bold;" target="_blank" title="Click to know more about STRENGTH">STRENGTH</a> `~=(300)/(10)~=<a href="https://interviewquestions.tuteehub.com/tag/30-304807" style="font-weight:bold;" target="_blank" title="Click to know more about 30">30</a>`</body></html>