10 ml of a mixture of carbon monoxide, marsh gas and hydrogen exploded with excess of oxygen gave a contraction of 6.5cc. There was further contraction of 7cc when the residual gas was treated with caustic potash. The volume of marsh gas present in original mixture as

10 ml of a mixture of carbon monoxide, marsh gas and hydrogen exploded

1.	10 ml of a mixture of carbon monoxide, marsh gas and hydrogen exploded with excess of oxygen gave a contraction of 6.5cc. There was further contraction of 7cc when the residual gas was treated with caustic potash. The volume of marsh gas present in original mixture as
Answer» 5cc 2cc 3cc 4cc Solution :VOLUME of CO = xCC Volume of MARSH GAS = yCC Volume of nitrogen = `10-(x+y)C C` `{:("2 CO",+,"O2",rarr,2CO_(2)),("x CC",,(x)/(2)"CC",,"xCC"):}` `{:(CH_(4)(g)+2O_(2)(g)rarrCO_(2)(g)+2H_(2)O(l)),(""darr),("YCC2yCCyCCvolume negligible"):}` Contraction in volume due to bruning of CO `=x+(x)/(2)-x-(x)/(2)C C` Contraction in volume due to burning of `CH_(4)` `=y+2y-y=2yC C` `(x)/(2)+2y=6.5C Corx+4y=13C C` volume of `CO_(2)` produced = `x+y` contraction in volume with caustic POTASH = 7CC `x+4y=13impliesx+y=7impliesy=2impliesx=5` `CO=5C C""CH_(4)=2C C""N_(2)=3C C`