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10 " mL of " a solution of H_(2)O_(2) of 10 violume strength decolourises 100 " mL of " KMnO_(4) solution acidified with dil H_(2)SO_(4). The amount of KMnO_(4) in the given solution is K=39, Mn=55) |
Answer» <html><body><p>0.282 g<br/>0.564 g<br/>1.128g<br/>0.155 g</p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/volume-728707" style="font-weight:bold;" target="_blank" title="Click to know more about VOLUME">VOLUME</a> of `O_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)` at STP`=10mLxx10V=100mL` <br/> `22400" mL of " O_(2) at STP =1 mol=4Eq` <br/> `100 " mL of " O_(2) STP=(4)/(22400)xx100=(1)/(56)<a href="https://interviewquestions.tuteehub.com/tag/eq-446394" style="font-weight:bold;" target="_blank" title="Click to know more about EQ">EQ</a>` <br/> " Eq of "`KMnO_(4)=" Eq of "O_(2)` <br/> `=(1)/(56)" Eq of "KMnO_(4)` <br/> `=(1)/(56)xx31.5g of KMnO_(4)` <br/> `=0.564g` <br/> `(Ew of KMnO_(4)` in acidic medium `=(<a href="https://interviewquestions.tuteehub.com/tag/mw-550075" style="font-weight:bold;" target="_blank" title="Click to know more about MW">MW</a>)/(5)=31.5`)</body></html> | |