10 ml of H_(2)O_(2) could release 224 ml of O_(2) at 273K and 2 atm pressure. What is the molarity of that H_(2)O_(2)

10 ml of H_(2)O_(2) could release 224 ml of O_(2) at 273K and 2 atm pr

1.	10 ml of H_(2)O_(2) could release 224 ml of O_(2) at 273K and 2 atm pressure. What is the molarity of that H_(2)O_(2)
Answer» Solution :`N=(PV)/(RT)= n(2xx224xx10^(-3))/(0.0821xx273)` `n=(2xx224xx10^(-3))/(22.4) rArr n=2xx10^(-2) "MOLES" of O_(2)` `2H_(2)O_(2) to 2H_(2)O+O_(2)` `4xx10^(-2)` moles `2xx10^(-2)` moles `M=(n)/(Vlit)=(4xx10^(-2)xx1000)/(10), M=4`