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10 ml of H_(2)O_(2) could release 224 ml of O_(2) at 273K and 2 atm pressure. What is the molarity of that H_(2)O_(2)

Answer» <html><body><p><br/></p>Solution :`<a href="https://interviewquestions.tuteehub.com/tag/n-568463" style="font-weight:bold;" target="_blank" title="Click to know more about N">N</a>=(PV)/(RT)= n(2xx224xx10^(-3))/(0.0821xx273)` <br/> `n=(2xx224xx10^(-3))/(22.4) rArr n=2xx10^(-<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>) "<a href="https://interviewquestions.tuteehub.com/tag/moles-1100459" style="font-weight:bold;" target="_blank" title="Click to know more about MOLES">MOLES</a>" of O_(2)` <br/> `2H_(2)O_(2) to 2H_(2)O+O_(2)` <br/> `4xx10^(-2)` moles `2xx10^(-2)` moles <br/> `M=(n)/(Vlit)=(4xx10^(-2)xx1000)/(10), M=4`</body></html>


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