10 ml of HCI solution gave 0.1435 gm of AgClwhen treated with excess of AgNO3. The normalityof the HCl solution is:(3) 0.3(4) 0.2

10 ml of HCI solution gave 0.1435 gm of AgClwhen treated with excess o

1.	10 ml of HCI solution gave 0.1435 gm of AgClwhen treated with excess of AgNO3. The normalityof the HCl solution is:(3) 0.3(4) 0.2
Answer» HCl + AgNO3 …............>AgCl+ HNO310ml …...excess .... ….............00ml …..excess.. …..................0.1435g...................................................=(0.1435/143.5) mol=0.001mol AgCl made by 10 ml of HClFrom reaction it is clear that,1 mole of AgCl would be obtained by1 mole HClSo number of moles of HCl in 10ml would be=0.001SO number of equivalents of HCl in 10ml = 0.0011 …..(as basicity of HCl =1)Hence normality of HCl=(number of equivalents of HCl/volume of HCl in ml)1000normality= (0.001/10)*1000=0.1N