10 ml of na2co3 solution having 5.3 g/l requires 20 ml of 0.05 N hno3 for complete neutralization calculate the equivalent mass of na2co3

10 ml of na2co3 solution having 5.3 g/l requires 20 ml of 0.05 N hno3

1.	10 ml of na2co3 solution having 5.3 g/l requires 20 ml of 0.05 N hno3 for complete neutralization calculate the equivalent mass of na2co3
Answer» H of NA2CO3 is 5.3 Normaliry of it is STRENGTH by eqvivalent N1v1=n2v2 EQN of NEUTRALIZATION