10 moles of an ideal gas expand isothermally and reversibly from a pressure of5 atm to 1 atm at300 K . What is thelargest mass that can be lefted through a height of 1 metre by this expansion?

10 moles of an ideal gas expand isothermally and reversibly from a pre

1.	10 moles of an ideal gas expand isothermally and reversibly from a pressure of5 atm to 1 atm at300 K . What is thelargest mass that can be lefted through a height of 1 metre by this expansion?
Answer» <html><body><p></p>Solution :`w_(exp) = - 2.303 nRT log.(P_(1))/(P_(2))=-2.303 ( <a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a> mol) xx( 8.314 <a href="https://interviewquestions.tuteehub.com/tag/jk-521675" style="font-weight:bold;" target="_blank" title="Click to know more about JK">JK</a>^(-1) mol^(-1)) ( <a href="https://interviewquestions.tuteehub.com/tag/300-305868" style="font-weight:bold;" target="_blank" title="Click to know more about 300">300</a> <a href="https://interviewquestions.tuteehub.com/tag/k-527196" style="font-weight:bold;" target="_blank" title="Click to know more about K">K</a> ) log. ( 5)/(1) = - 40.15 xx 10^(3)J` <br/>If M is the mass that can be lifted by this work ,through a height of 1metre, then work done `=` Mgh <br/> ` 40.15xx 10^(3)J= Mxx9.81 m s^(-2) xx 1m` <br/> or ` M =( 40.15 xx10^(3) kg m^(2) s^(-2))/( 9.18 ms^(-2)xx 1 m ) (J = kg m^(2) s^(-2))` <br/> `= 4092 .76 kg`</body></html>