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10. Prove that :x2 + y2 + z2 - xy - yz - zx is always positive. |
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Answer» I want the solving x²+y²+z²-xy-yz-zx =1/2[2x²+2y²+2z²–2xy-2yz-2zx] =(1/2)[(x²+y²–2xy(+(y²+z²–2yz)+(z²+x²–2zx)] =(1/2)[(x-y)²+(y-z)²+(z-x)²] =Always positive since ( All squres are +ve) |
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