10.The percentage weight of Zn in white vitriolIZnSO,.7H201 is approxi

1.	10.The percentage weight of Zn in white vitriolIZnSO,.7H201 is approximately equal toIAIPMT 1995](Zn = 65,S = 32.0 = 16 and H = 1)(A) 33.65%(C) 23.65%(B) 32.56%(D) 22.65%
Answer» White vitriol is the compound known as zinc sulphate Which has the formula ZnSO₄ mass percent = (mass of element in 1 mole of compound / mass of 1 mole of compound) x 100 mass of Zn = 65.4mass of S = 32mass of O = 16 There mass of 1 mole ofZnSO₄ = 65.4 + 32 + (16×4)= 161.4 % mass of zinc = 65.4/161.4 × 100% = 40.5% The most commonly encountered form of this compound is zinc sulphate heptahydrate Formula: ZnSO₄.7H₂O mass of 1 mole of it is 161.4 + (18x7) =287.4 % mass of zinc in the heptahydrate = 65.4/287.4× 100% = 22.76%

10.The percentage weight of Zn in white vitriolIZnSO,.7H201 is approximately equal toIAIPMT 1995](Zn = 65,S = 32.0 = 16 and H = 1)(A) 33.65%(C) 23.65%(B) 32.56%(D) 22.65%

Answer»

White vitriol is the compound known as zinc sulphate

Which has the formula ZnSO₄

mass percent = (mass of element in 1 mole of compound / mass of 1 mole of compound) x 100

mass of Zn = 65.4mass of S = 32mass of O = 16

There mass of 1 mole ofZnSO₄

= 65.4 + 32 + (16×4)= 161.4

% mass of zinc = 65.4/161.4 × 100% = 40.5%

The most commonly encountered form of this compound is zinc sulphate heptahydrate

Formula: ZnSO₄.7H₂O

mass of 1 mole of it is 161.4 + (18x7) =287.4

% mass of zinc in the heptahydrate = 65.4/287.4× 100% = 22.76%