InterviewSolution
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InterviewSolution
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`100` capacitors each having a capacity of `10 muF` are connected in parallel and are charged by a potential difference of `100 kV`. The energy stored in the capacitors and the cost of charging them, if electrical energy costs `108` paise per `kWh`, will beA. `10^(7)` and 300 paiseB. `5xx10^(6)J` and 300 paiseC. `5xx10^(6)J` and 150 paiseD. `10^(7)J` and 750 paise |
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Answer» Correct Answer - C Equivalence capacitance of n. Capacitor in parallel, `C=nc_(1)=100xx10muF =1000muF=10^(-3)F` Energy stored, `U=(1)/(2)CV^(2)=(1)/(2)xx10^(-3)xx(10^(5))^(2)` `=5xx10^(8)J=(5xx10^(6))/(3.6xx10^(6))kWJ` Net cost `=(5xx10^(6))/(3.6xx10^(6))xx10^(6)="150 paise"` |
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