100 g of ice at 0^(@)C is mixed with 100 g of water at 80^(@)C. The resulting temperature is 6^(@)C. Calculate heat of fusion of ice.

100 g of ice at 0^(@)C is mixed with 100 g of water at 80^(@)C. The re

1.	100 g of ice at 0^(@)C is mixed with 100 g of water at 80^(@)C. The resulting temperature is 6^(@)C. Calculate heat of fusion of ice.
Answer» Solution :`overset("ICE")(at0^(@)C)rarroverset(water)(at0^(@)C)rarroverset(water)(at6^(@)C)` `m_(1)c_(1)(80-6)=m_(2)L+m_(2)c_(2)(6-0)` `100xx1xx74=100L+100xx1xx6` `L=(1xx74)-6` `=68cal//g.`