1.

100 ml 0.1 M H_3PO_4 solution is being titrated with 0.1 M NaOHsolution. The pH of the reaction mixture keeps increasing with addition of NaOH. The successive dissociation constant of H_3PO_4 " are "10^(-3) , 10 ^(-6) and 10^(-14)respectively. What is the pH of the reaction mixture after adding 50 ml of NaOH ?

Answer»

`3`
`4`
`6`
`5.3`

Solution :After ADDING 50 ml NaOH, buffer ` (H_3PO_4 + NaH_2 PO_4) ` with MAXIMUM capacity is obtained.
` therefore pH =P^(Ka_2) =3`


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