100 ml, 0.1 M K_(2)SO_(4) is mixed with 100 ml, 0.1M Al_(2)(SO_(4))_(3) solution. The resultant solution is

100 ml, 0.1 M K_(2)SO_(4) is mixed with 100 ml, 0.1M Al_(2)(SO_(4))_(3

1.	100 ml, 0.1 M K_(2)SO_(4) is mixed with 100 ml, 0.1M Al_(2)(SO_(4))_(3) solution. The resultant solution is
Answer» `0.1NK^(+)` ions `0.4NK^(+)` ions `0.2MSO_(4)^(-2)` ions `0.1MAl^(+3)` ions SOLUTION :`[K^(+)]=(100xx0.1xx2)/(200)=0.1M=0.1N` `[SO_(4)^(2-)]=(100xx0.1xx1+100xx0.1xx3)/(200)` `=0.2M=0.4N` `[AL^(+3)]=(100xx0.1xx2)/(200)=0.1M=0.3N`