100 ml, 1.5M Fe(NO_(3))_(3). 100 ml, 2M FeCl_(3), 100 ml 2M Mg(NO_(3))_(2) are mixed and 700 ml water is added. The molar concentration of total ions in the solution in ______M

100 ml, 1.5M Fe(NO_(3))_(3). 100 ml, 2M FeCl_(3), 100 ml 2M Mg(NO_(3))

1.	100 ml, 1.5M Fe(NO_(3))_(3). 100 ml, 2M FeCl_(3), 100 ml 2M Mg(NO_(3))_(2) are mixed and 700 ml water is added. The molar concentration of total ions in the solution in ______M
Answer» Solution :Total MOLES of ions from `Fe(NO_(3))_(3)` `=0.1xx1.5xx4=0.6` From `FeCl_(3)=0.1xx2xx4=0.8` From `MG(NO_(3))_(2)=0.1xx2xx3=0.6` `therefore` Total moles of ions = 2 `therefore M=(2)/(1)=2M`