100 ml aqueous 0.1 molar M(CN)_(2), (80% ionized) solution is mixed with 100 ml of 0.05 molar H_(2),SO_(2) solution (80% ionized). (K_(6), of CN" = 10^(-6))

100 ml aqueous 0.1 molar M(CN)_(2), (80% ionized) solution is mixed wi

1.	100 ml aqueous 0.1 molar M(CN)_(2), (80% ionized) solution is mixed with 100 ml of 0.05 molar H_(2),SO_(2) solution (80% ionized). (K_(6), of CN" = 10^(-6))
Answer» `6` `8` `9` `7` Solution :`M(CN)_2 hArr M^(+2)+ 2CN^(-) ` `10m " moles" ` ` {:( 10(1- alpha ) , 10 alpha =8 , 2 xx 10 alpha = 16 ),( H_2SO_4 hArr, 2H^(+) , SO_4^(2-)),( 5 " moles" ,,),(5(1- beta ), 2 xx 5 beta =8, 5 beta =4 ), (H^(+) + , CN^(-) hArr, HCN),( 8,16,):}` `8,8 ` i.e., BUFFER of HCN & `CN^(-) ` ` therefore PH =pKa +LOG ""( S)/(A)=pKa =14 -6=8`