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100 mL each of 1NH_(2)O_(2) " and " 11.2 V H_(2)O_(2) solution are mixed, then the resultant solution will be :

Answer» <html><body><p>`3M H_(2)O_(2)`<br/>`0.5 <a href="https://interviewquestions.tuteehub.com/tag/n-568463" style="font-weight:bold;" target="_blank" title="Click to know more about N">N</a> H_(2)O_(2)`<br/>`25.5 g//L H_(2)O_(2)`<br/>`2.55 g//L H_(2)O_(2)`</p>Solution :`11.2V H_(2)O_(2)-=(11.2)/(5.6)N H_(2)O_(2) i.e., 2N H_(2)O_(2)` <br/> `N_(1)V_(1)+N_(2)V_(2)=N_(R )(V_(1)+V_(2))` <br/> `1xx100+2xx100=N_(R )xx200` <br/> `N_(R )=(3)/(2)=1.5` <br/> Strength `=N xx " Equivalent <a href="https://interviewquestions.tuteehub.com/tag/mass-1088425" style="font-weight:bold;" target="_blank" title="Click to know more about MASS">MASS</a>"` <br/> `=1.5xx17=25.5 g//L`</body></html>


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