100 mL each of 1NH_(2)O_(2) " and " 11.2 V H_(2)O_(2) solution are mixed, then the resultant solution will be :

100 mL each of 1NH_(2)O_(2) " and " 11.2 V H_(2)O_(2) solution are mix

1.	100 mL each of 1NH_(2)O_(2) " and " 11.2 V H_(2)O_(2) solution are mixed, then the resultant solution will be :
Answer» `3M H_(2)O_(2)` `0.5 N H_(2)O_(2)` `25.5 g//L H_(2)O_(2)` `2.55 g//L H_(2)O_(2)` Solution :`11.2V H_(2)O_(2)-=(11.2)/(5.6)N H_(2)O_(2) i.e., 2N H_(2)O_(2)` `N_(1)V_(1)+N_(2)V_(2)=N_(R )(V_(1)+V_(2))` `1xx100+2xx100=N_(R )xx200` `N_(R )=(3)/(2)=1.5` Strength `=N xx " Equivalent MASS"` `=1.5xx17=25.5 g//L`