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100 ml `Fe(OH)_(3)` is coagulated by 10 ml 1N `Na_(2)SO_(4)`. Then what will be coagulation value of `Na_(2)SO_(4)`?A. 5B. 10C. 50D. 100 |
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Answer» Correct Answer - C 100 ml `Fe(OH)_3 ` is coagulated by =`10xx1/2`=5 milli mol 1 mol `Fe(OH)_3` is coagulated by = `5/100` 1000 ml `Fe(OH)_3` is coagulated by `=(1000xx5)/100`=50 |
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