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100 mL of 0.05 M aqueous `CuSO_(4)` solution is subjected to electrolysis. Calculate the quantity of electricity required for the deposition of entire copper at the cathode.A. 0.005 FB. 0.01 FC. 0.1 FD. 0.05 F |
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Answer» `(W_(Cu))/(63.5) xx (1000)/(100) = 0.5 M` `rArr W_(Cu) = (0.05 xx 63.5)/(10) = 0.3175 g` NO. of equivalents `= (0.3175)/(31.75) = 0.01` `:.` No of Faradays is 0.01 F |
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