100 ml of 0.1 M HCl and 100 ml of 0.1 M HOCN are mixed then(K_a= 1.2 x

1.	100 ml of 0.1 M HCl and 100 ml of 0.1 M HOCN are mixed then(K_a= 1.2 xx 10^(-6))
Answer» `OCN^(-) `concentration in the solution is `1.2 xx10^(-6) ` pH of the solution is 1.3 solution is a buffer `H^(+) ` in the solution is `10^(6) ` Solution :`HOCNhArr H^(+) +OCN^(-) ` ` K_a RARR ([H^(+)][OCN^(-)])/( [HOCN]) ` ` 1.2 xx 10 ^(-6)= (5xx 10 ^(_2)[OCN^(-) ])/( 5 xx10 ^(-2)) ` `[ OCN^(-)]= 1.2 xx 10 ^(-6) ` Approximation method, WEAK acid conribution is neglected. ` [H^(+) ] =(100 xx 0.1 +0)/( 200) = 0.05 therefore pH =1.3 `

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