1.

100 ml of 0.1 M HCl and 100 ml of 0.1 M HOCN are mixed . What is the concentrationof .. OCN ^(-)..,and pH of the solution ?(K_a=1.2 xx 10^(-6) )

Answer»

` 1.2 xx 10^(-6), 1.3 `
` 1.2 xx 10^(-6),1`
` 2.6 xx 10^(-8),1.6`
` 2.4 xx 10^(-6), 2.6`

SOLUTION :`[H^(+)]= (100 xx 0.1 )/(200)=0.05,pH =2- log 5 =13`
`[HOCN]=( 100xx 0.1 )/( 200) = 0.05`
` K_a =([H^(+) ][OCN^(-) ])/( [HOCN])=(1.2 xx 10 ^(-6) xx 0.05 )/( 0.05 ) `
` = [OCN^(-) ]=1.2 xx 10^(-6) `


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