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100 ml of 0.1 M HCl and 100 ml of 0.1 M HOCN are mixed . What is the concentrationof .. OCN ^(-)..,and pH of the solution ?(K_a=1.2 xx 10^(-6) ) |
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Answer» ` 1.2 xx 10^(-6), 1.3 ` `[HOCN]=( 100xx 0.1 )/( 200) = 0.05` ` K_a =([H^(+) ][OCN^(-) ])/( [HOCN])=(1.2 xx 10 ^(-6) xx 0.05 )/( 0.05 ) ` ` = [OCN^(-) ]=1.2 xx 10^(-6) ` |
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