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100 ml of 0.5 M H2SO4 solution is neutralized by 50 ml of 0.1 M NaOH and x ml of 0.1 MCa(OH)2. The value of x is(1) 200 ml (2) 370 ml(3) 475 ml (4) 405 ml |
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Answer» Answer: 100 mL of 0.5 M H2SO4 is used. 0.1 L of 0.5 M H2SO4 is used. moles of H2SO4 = 0.5 x 0.1 => 0.05 moles of H2SO4. As 50 mL of 0.1 M NaOH is utilized completely |
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