100 ml of a solution of sodium hydroxide is found to be completely neu

1.	100 ml of a solution of sodium hydroxide is found to be completely neutralized by 80 ml of given solution of HCL to form a true solution of sodium chloride salt what will be the amount of hydrochloric acid required to neutralize 200 ml of the same solution of sodium hydroxide
Answer» Answer :- Given That 100 ml of SODIUM hydroxide is neutralized by 80ml of HCL . And , There is 200ml of Sodium hydroxide. Let the HCl required be X We KNOW Ratio is always proportional. So, 100/80 = 200/X X = (200 × 80)/100 X = 2 × 80 X = 160 Hence, 160ml of HCl is REQUIRED to neutralize 200ml of NAOH (sodium hydroxide)

100 ml of a solution of sodium hydroxide is found to be completely neutralized by 80 ml of given solution of HCL to form a true solution of sodium chloride salt what will be the amount of hydrochloric acid required to neutralize 200 ml of the same solution of sodium hydroxide

Answer»

Answer :-

Given That

100 ml of SODIUM hydroxide is neutralized by 80ml of

HCL .

And , There is 200ml of Sodium hydroxide.

Let the HCl required be X

We KNOW Ratio is always proportional.

So,

100/80 = 200/X

X = (200 × 80)/100

X = 2 × 80

X = 160

Hence, 160ml of HCl is REQUIRED to neutralize 200ml of NAOH (sodium hydroxide)

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100 ml of a solution of sodium hydroxide is found to be completely neutralized by 80 ml of given solution of HCL to form a true solution of sodium chloride salt what will be the amount of hydrochloric acid required to neutralize 200 ml of the same solution of sodium hydroxide​