100 mL of each pH = 3 and pH = 5 solutions of a strong acid are mixed. What is the resultant pH ?

100 mL of each pH = 3 and pH = 5 solutions of a strong acid are mixed.

1.	100 mL of each pH = 3 and pH = 5 solutions of a strong acid are mixed. What is the resultant pH ?
Answer» Solution : PH of first solution `= 3, [H^(+) ]=10^(-3)=N_1` pH of second solution `= 5, [H^(+) ]=10^(-5) = N_2` Final PROTON concentration is GIVEN by the equation:`[H^+]=(V_1 N_1+V_2 N_2)/(V_1 +V_2)` Substituting the values` [H^(+)] =(100 XX 10^(-3) xx 10^(-5))/( 100+100 ) = 5.05 xx 10^(-4)` M pH of the resultant mixture `= -log (5.05 xx 10^(-4) ) = 4 - log 5.05 = 3.3`