100 mL of H_(2)O_(2) is oxidized by 100 mL of 1M KMnO_(4) in acidic medium (MnO_(4)^(-) reduced to Mn^(+2) ) 100 mL of same H_(2)O_(2) is oxidized by v mL of 1M KMnO_(4) in basic medium (MnO_(4)^(-)reduced to MnO_(2)). Findthe value of v:

100 mL of H_(2)O_(2) is oxidized by 100 mL of 1M KMnO_(4) in acidic me

1.	100 mL of H_(2)O_(2) is oxidized by 100 mL of 1M KMnO_(4) in acidic medium (MnO_(4)^(-) reduced to Mn^(+2) ) 100 mL of same H_(2)O_(2) is oxidized by v mL of 1M KMnO_(4) in basic medium (MnO_(4)^(-)reduced to MnO_(2)). Findthe value of v:
Answer» 500 100 `100//3` `500//3` Solution :In acidic medium Eqts of `H_(2)O_(2)` = Eqts of `KMnO_(4)` `(100)/(1000)xxMxx2=(100)/(1000)xx1xx5impliesM=2.5` In basic medium Eq. of `H_(2)O_(2)` = Eqts of `KMnO_(4)` `(100)/(1000)xx2.5xx2=(V)/(1000)xx1xx3impliesV=(500)/(3)`