100 mL of H_(2)O_(2) is oxidized by 100 mL of 1M KMnO_(4) in acidic medium (MnO_(4)^(-) reduced to Mn^(+2) ) 100 mL of same H_(2)O_(2) is oxidized by v mL of 1M KMnO_(4) in basic medium (MnO_(4)^(-)reduced to MnO_(2)). Findthe value of v:

100 mL of H_(2)O_(2) is oxidized by 100 mL of 1M KMnO_(4) in acidic me

1.	100 mL of H_(2)O_(2) is oxidized by 100 mL of 1M KMnO_(4) in acidic medium (MnO_(4)^(-) reduced to Mn^(+2) ) 100 mL of same H_(2)O_(2) is oxidized by v mL of 1M KMnO_(4) in basic medium (MnO_(4)^(-)reduced to MnO_(2)). Findthe value of v:
Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/500-323288" style="font-weight:bold;" target="_blank" title="Click to know more about 500">500</a><br/><a href="https://interviewquestions.tuteehub.com/tag/100-263808" style="font-weight:bold;" target="_blank" title="Click to know more about 100">100</a><br/>`100//3`<br/>`500//3`</p>Solution :In acidic medium <br/> Eqts of `H_(2)O_(2)` = Eqts of `KMnO_(<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>)` <br/> `(100)/(<a href="https://interviewquestions.tuteehub.com/tag/1000-265236" style="font-weight:bold;" target="_blank" title="Click to know more about 1000">1000</a>)xxMxx2=(100)/(1000)xx1xx5impliesM=2.5` <br/> In basic medium <br/> Eq. of `H_(2)O_(2)` = Eqts of `KMnO_(4)` <br/> `(100)/(1000)xx2.5xx2=(V)/(1000)xx1xx3impliesV=(500)/(3)`</body></html>