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100 mL of `PH_(3)` on decomposition produced phosphorus and hydrogen. The change in volume isA. 50 mL increaseB. 500 ml decreaseC. 900 mL decreaseD. nil |
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Answer» Correct Answer - A `underset(2vol)(2PH_(3))tounderset(3vol)(3H_(2))+2P` 2 vol of `PH_(3)` give 3 vol of `H_(2)` `:.` 100 mL of `PH_(3)` gives 150 mL of `H_(2)` `:.` Increases in volume = 150 mL - 100 mL = 50 mL |
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