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100 mL of pH = 6 (acidic) is diluted to 1000 mL by H2O. pH will increase approximately by:(a) 9 unit (b) 1 unit(c) 0.7 unit (d) –0.7 unit |
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Answer» Correct option: (c) 0.7 Explanation: On dilution, N1V1 = N2V2 10–6 x 100 = N2 x 1000 N2 = 10–7 N Since acid solution has pH < 7, it will remain acidic even after dilution, Hence, total [H+] = [H+]acid + [H+]water = 10–7 + 10–7 = 2 x 10–7 N ∴ pH = – log [H+] = – log (2 x 10–7) = 7 – log 2 = 6.7 Thus, change in pH = 0.7 unit |
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