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100 mL of phosphorus pentachloride is totally decomposed to its trichloride at 1 atm and 546^(@)C. How many molecules of chlorine are formed? |
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Answer» Solution :DECOMPOSITION of phosphorus pentachloride is given as `PCl_(5)rarrPCl_(3)+Cl_(2)` `"1 mole of "PCl_(5)="1 mole of"Cl_(2)` `"1 vol of "PCl_(5)="1 vol FO Cl"_(2)` `"100 mL of "PCl_(5)="100 mL of "Cl_(2)` `{:("Given conditions","STP conditions"),(P_(1)="1 atm",P_(2)="1 atm"),(T_(1)="819 K",T_(2)="273 K"),(V_(1)="100 mL",V_(2)=?):}` The VOLUE of `Cl_(2)` MEASURED at STP `V_(2)=(P_(1)V_(1))/(T_(1))xx(T_(2))/(P_(2))=(1xx100xx273)/(819xx1)="33.33mL"` `"22400 mL of "Cl_(2)" at STP"=` `6.022xx10^(23)" molecules"` `"33.33 mL of "Cl_(2)" at STP"=?` Number of molecules of chlorine obtained `=(33.33)/(22400)xx6.022xx10^(23)=8.96xx10^(20)` |
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