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100 ml of sample is removed from an aqueous solution saturated with CaSO_(4) at 25^(0)C. The water is completely evaported from the sample and deposit of 0.24 g of CaSO_(4) is obtained. The Ksp of CaSO_(4) at 25^(0)C will be.

Answer» <html><body><p>`3.115 xx 10^(-4)`<br/>`3.115 xx 10^(-5)`<br/>`3.115 xx 10^(-6)`<br/>`3.115 xx 10^(-3)`</p>Solution :`CaSO_(4(s))hArrCa_((aq))^(+2) + SO_(4(aq))^(2-), Ksp = ?` <br/> According to the given <a href="https://interviewquestions.tuteehub.com/tag/data-25577" style="font-weight:bold;" target="_blank" title="Click to know more about DATA">DATA</a>, solubility of `CaSO_(4)` is `0.24 g` <a href="https://interviewquestions.tuteehub.com/tag/per-590802" style="font-weight:bold;" target="_blank" title="Click to know more about PER">PER</a> `<a href="https://interviewquestions.tuteehub.com/tag/100-263808" style="font-weight:bold;" target="_blank" title="Click to know more about 100">100</a> ml` <br/> `[<a href="https://interviewquestions.tuteehub.com/tag/ca-375" style="font-weight:bold;" target="_blank" title="Click to know more about CA">CA</a>^(+2)] = [SO_(4)^(2-)] = 0.01765 M` <br/> `Ksp = [Ca^(+2)] [SO_(4)^(2-)]`</body></html>


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