InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
100 ml solution having 0.2 M HA (weak acid, K_(a), = 1.0x10^(-5) ) and 0.2 N NaA, 200 ml of 0.1 M NaOH has been added. Furthermore, diluted to IL. Which of the following statement is correct? |
| Answer» <html><body><p>Initially , the <a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> has pH equal to 5, that is before additions of NaOH <br/>In the final solution , the <a href="https://interviewquestions.tuteehub.com/tag/concentration-20558" style="font-weight:bold;" target="_blank" title="Click to know more about CONCENTRATION">CONCENTRATION</a> of `[OH^(-) ] is 10^(-9) ` M. <br/>After the addition of NaOH , the pH of solution increase by four units. <br/>After the addition of base, the solution losses buffering action and can be restored after the addition of acid. </p>Solution :Initially acid buffer is present <br/><br/> ` pH =5+ <a href="https://interviewquestions.tuteehub.com/tag/log-543719" style="font-weight:bold;" target="_blank" title="Click to know more about LOG">LOG</a> ""(0.2)/( 0.2)= 5` <br/> (b)after dilution to1 <a href="https://interviewquestions.tuteehub.com/tag/lt-537906" style="font-weight:bold;" target="_blank" title="Click to know more about LT">LT</a>, <br/> ` [HA] =0.02 N, [NaA ]= 0.02 N` <br/> ` [NaOH ]=0.02 N` <br/> ` {:( NaOH +, HA to , NaA + H_2O) , (0.02 N , 0.02N , -),( -,-,0.02N):}` <br/> ` therefore` Due to addition of NaOH , buffer disappeared & salt is formed <br/> ` pH =7+ ( 5)/(2) +(1)/(2) log (4 <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> 10 ^(-2)) = 8.8 `</body></html> | |