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100 ml solution having 0.2 M HA (weak acid, K_(a), = 1.0x10^(-5) ) and 0.2 N NaA, 200 ml of 0.1 M NaOH has been added. Furthermore, diluted to IL. Which of the following statement is correct? |
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Answer» Initially , the SOLUTION has pH equal to 5, that is before additions of NaOH ` pH =5+ LOG ""(0.2)/( 0.2)= 5` (b)after dilution to1 LT, ` [HA] =0.02 N, [NaA ]= 0.02 N` ` [NaOH ]=0.02 N` ` {:( NaOH +, HA to , NaA + H_2O) , (0.02 N , 0.02N , -),( -,-,0.02N):}` ` therefore` Due to addition of NaOH , buffer disappeared & salt is formed ` pH =7+ ( 5)/(2) +(1)/(2) log (4 XX 10 ^(-2)) = 8.8 ` |
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