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1000 drops of a liquid each of diameter 4 mm coalesce to form a single large drop. If surface tension of liquid is 35 dyne cm^(-1). Calculate the energy evolved by the system in the process. |
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Answer» Solution :Number of drops `N=1000impliesn^(1//3)=10` `implies n^(2//3)=100` Surface tension of liquid `S=35" dyne cm"^(-1)` Radius of each small drop `r=2mm=0.2cm` Energy evolved in MERGING `W=4pir^(2)S[n-n^(2//3)]` `impliesW=4xx(22)/(7)xx(2xx10^(-1))^(2)35(1000-100]` `implies W=(88xx35xx4xx10^(-2))/(7)[900]` `=15840" ergs".~~1.58xx10^(-3)J` |
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