1.

1000 identical drops of mercury are charged to a potential of 1 V each. They join to form a single drop. The potential of this drop will be (a) 0.01 V (b) 0.1 V (c) 10 V (d) 100 V

Answer»

Correct Answer is: (d) 100 V

Volume = 4/3 πR3 = 1000 x 4/3 πr3 or r = R/10

Q = CV = (4πε0R) x V = 1000(4πε0r) 1 

or V = 103 τ/R = 103/10 = 100 V



Discussion

No Comment Found

Related InterviewSolutions