1.

100kg of a sample of water contained 6 of MgSO_(4) The degree of

Answer»

6 ppm
60 ppm
5 ppm
500 ppm

Solution :`100 kg=10^(5)g rArr "weight" of MgSO_(4)=6G`
HARDNESS of `MgSO_(4)=(6g)/(10^(5)g)xx10^(6)=60ppm`
hardness in term of
`CaCO_(3)=60xx(100)/(120)=50` ppm


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