1.

100ml of 0.01 M solution of NaOH is diluted to 1dm^(3). What is the pH of the diluted solution

Answer»

12
11
2
3

Solution :100 ML 0.01 M NaOH solution is DILUTED to `1 dm^(3)` (i.e., 10 times dluted) hence, the resultant solution will be 0.001 M.
`:. [OH^(-)] = 0.001 = 10^(-3)`
`[H^(+)] = (10^(-14))/([OH^(-)]) = (10^(-14))/(10^(-3)) = 10^(-11)`
`because pH = - log[H^(+)] = -log[10^(-11)]`
pH = 11.


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