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102 g of solid NH_(4)HS is taken in the 2L evacuated flask at 57^(@). Following two equilibrium exist simultaneously NH_(4)(s)iffNH_(3)(g)+H_(2)S(g) NH_(3)(g)iff(1)/(2)N_(2)(g)+(3)/(2)H_(2)(g) one mole of the solid decomposes to maintain both the equilibrium and 0.75 mol e of H_(2) was found at the equilibrium then find the equilibrium concentration of all the species and K_(C) for the both the reaction.

Answer» <html><body><p></p>Solution :Moles of `NH_(4)HS=(102)/(51)=<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>` <br/> `NH_(4)(s)iffNH_(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)(g)+H_(2)S(g)` <br/> `{:(2,0,0),(1,1-x,1):}` <br/> `NH_(3)(g)<a href="https://interviewquestions.tuteehub.com/tag/iff-1036748" style="font-weight:bold;" target="_blank" title="Click to know more about IFF">IFF</a>(1)/(2)N_(2)(g)+(3)/(2)H_(2)(g) K_(C_(2))`<br/> `1-x (x)/(2) (3x)/(2)` <br/> Given that moles of `H_(2)=(3x)/(2)=0.75 iff x=(1)/(2)` <br/> `K_(C_(2))=1/2 ((1-x))/(2)=1/8` [<a href="https://interviewquestions.tuteehub.com/tag/since-644476" style="font-weight:bold;" target="_blank" title="Click to know more about SINCE">SINCE</a> `V=2L`] <br/>`K_(C_(2))=(((3x)/(4))^(3//2)((x)/(4))^(1//2))/(((1-x)/(2)))=(((3)/(8))^(3//2)((1)/(8))^(1//2))/(1/4)=(3)^(3//2)1/64xx4/1=(3)^(3//2)/(16)`</body></html>


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