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10g of hydrogen and 64g |
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Answer» ong>Answer:2H
10 g of hydrogen (MOLAR mass 2 g/MOL) = 2 g/mol 10 g = 5 mol 64 of oxygen (molar mass 32 g/mol) = 32 g/mol 64 g = 2 mol As per the balanced CHEMICAL equation, 1 mole of oxygen will react with 2 moles of hydrogen to form 2 moles of water.
2 moles of oxygen will react with 2×2=4 moles of hydrogen to form 4 moles of water. Here, oxygen is the limiting reagent and hydrogen is the excess reagent. Hence, option B is correct |
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