10ml of mixture containing CO and N_(2) required 7 ml of oxygen to form CO_(2) and NO respectively on combution. Find the volume of N_(2) in the mixture.

10ml of mixture containing CO and N_(2) required 7 ml of oxygen to for

1.	10ml of mixture containing CO and N_(2) required 7 ml of oxygen to form CO_(2) and NO respectively on combution. Find the volume of N_(2) in the mixture.
Answer» `7//2` `17//2` 4 ML 7 ml Solution :If VOL. of `CO=x` `CO+(1)/(2)O_(2)rarrCO_(2)` `underset(x)(CO)+(1)/(2)underset((x)/(2))(O_(2))rarrCO_(2)` `underset((10-x))(N_(2))+underset(10-x)(O_(2))rarr2NO` Vol. of `O_(2)` required = `(x)/(2)+10-x=10-(x)/(2)=7` `IMPLIES (x)/(2)=3impliesx=6mLimplies"vol."N_(2)=4mL`