10ml of mixture containing CO and N_(2) required 7 ml of oxygen to form CO_(2) and NO respectively on combution. Find the volume of N_(2) in the mixture.

10ml of mixture containing CO and N_(2) required 7 ml of oxygen to for

1.	10ml of mixture containing CO and N_(2) required 7 ml of oxygen to form CO_(2) and NO respectively on combution. Find the volume of N_(2) in the mixture.
Answer» <html><body><p>`7//2`<br/>`17//2`<br/>4 <a href="https://interviewquestions.tuteehub.com/tag/ml-548251" style="font-weight:bold;" target="_blank" title="Click to know more about ML">ML</a> <br/>7 ml</p>Solution :If <a href="https://interviewquestions.tuteehub.com/tag/vol-723961" style="font-weight:bold;" target="_blank" title="Click to know more about VOL">VOL</a>. of `CO=x` <br/> `CO+(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)/(2)O_(2)rarrCO_(2)` <br/> `underset(x)(CO)+(1)/(2)underset((x)/(2))(O_(2))rarrCO_(2)` <br/> `underset((10-x))(N_(2))+underset(10-x)(O_(2))rarr2NO` <br/> Vol. of `O_(2)` required = `(x)/(2)+10-x=10-(x)/(2)=7` <br/> `<a href="https://interviewquestions.tuteehub.com/tag/implies-1037962" style="font-weight:bold;" target="_blank" title="Click to know more about IMPLIES">IMPLIES</a> (x)/(2)=3impliesx=6mLimplies"vol."N_(2)=4mL`</body></html>