10Prove that in a right triangle, the square of the hypotenuse is equa

1.	10Prove that in a right triangle, the square of the hypotenuse is equal to sum of squares of other two sidesUsing the above result, prove that, in rhombus ABC25.AB AC2BD
Answer» Here, We see that, AO = 1/2AC BO = 1/2BD In triangle ABO, According to Pythagoras theorem, AO² + BO² = AB² (1/2AC)² + (1/2BD)² = AB² 1/4AC² + 1/4BD² = AB² 1/4 ( AC² + BD²) = AB² (AC² + BD²) = 4AB² [ Hence proved ] Like my answer if you find it useful!

10Prove that in a right triangle, the square of the hypotenuse is equal to sum of squares of other two sidesUsing the above result, prove that, in rhombus ABC25.AB AC2BD

Answer»

Here, We see that, AO = 1/2AC BO = 1/2BD

In triangle ABO,

According to Pythagoras theorem,

AO² + BO² = AB²

(1/2AC)² + (1/2BD)² = AB²

1/4AC² + 1/4BD² = AB²

1/4 ( AC² + BD²) = AB²

(AC² + BD²) = 4AB²

[ Hence proved ]

Like my answer if you find it useful!